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2 years ago

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Look at the two circles below. They share a center point. The larger circlehas a radius of 10 inches. The distance between the s

maller circle and the larger circle is 2 inches. Which best represents the shaded area between the two circles?
A138 square inches
138 square inches

B36 square inches
36 square inches

C515 square inches
515 square inches

D314 square inches
314 square inches

1 answer:

Alexxandr [17]2 years ago

8 0

B is the answer to the question

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The table represents an exponential function. A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4

scoray [572]

Answer:

The multiplicative rate of change of the function is $\dfrac{2}{3}$

Step-by-step explanation:

You are given the table

$\begin{array}{cc}x&y\\ \\1&6\\2&4\\ \\3&\dfrac{8}{3}\\ \\4&\dfrac{16}{9}\end{array}$

An exponential function can be written as

$y=a\cdot b^x,$

where b is the multiplicative rate of change of the function.

Find a and b. Substitute first two corresponding values of x and y into the function expression:

$6=a\cdot b^1\\ \\4=a\cdot b^2$

Divide the second equality by the first equality:

$\dfrac{4}{6}=\dfrac{a\cdot b^2}{a\cdot b^1}\Rightarrow b=\dfrac{2}{3}$

Substitute it into the first equality:

$6=a\cdot \dfrac{2}{3}\Rightarrow a=\dfrac{6\cdot 3}{2}=9$

So, the function expression is

$y=9\cdot \left(\dfrac{2}{3}\right)^x$

Check whether remaining two values of x and y suit this expression:

$9\cdot \left(\dfrac{2}{3}\right)^3=9\cdot \dfrac{8}{27}=\dfrac{8}{3}\\ \\9\cdot \left(\dfrac{2}{3}\right)^4=9\cdot \dfrac{16}{81}=\dfrac{16}{9}$

So, the multiplicative rate of change of the function is $\dfrac{2}{3}$

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2 years ago

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I need help now plz !

My name is Ann [436]

Answer:D

Step-by-step explanation:

students playing trombone=12+10+7+16

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2 years ago

Solve the following quadratic by<br> completing the square.<br> y = x^2 - 6x+7

kozerog [31]

Answer:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

Step-by-step explanation:

<u>Given quadratic equation</u>:

$y = x^2 - 6x+7$

To complete the square, begin by adding and subtracting the square of half the coefficient of the term in x:

$\implies y = x^2 - 6x+\left(\dfrac{-6}{2}\right)^2-\left(\dfrac{-6}{2}\right)^2+7$

$\implies y = x^2 - 6x+\left(-3\right)^2-\left(-3\right)^2+7$

$\implies y = x^2 - 6x+9-9+7$

Factor the perfect square trinomial:

$\implies y=(x-3)^2-9+7$

$\implies y=(x-3)^2-2$

To solve the quadratic, set it to zero and solve for x:

$\implies (x-3)^2-2=0$

$\implies (x-3)^2-2+2=0+2$

$\implies (x-3)^2=2$

$\implies \sqrt{(x-3)^2}=\sqrt{2}$

$\implies x-3= \pm\sqrt{2}$

$\implies x-3+3= 3\pm\sqrt{2}$

$\implies x= 3\pm\sqrt{2}$

Therefore, the solution to the given quadratic equation is:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

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Answer:

y-intercept: 0

slope:120/7

Step-by-step explanation:

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Answer: 8

Step-by-step explanation:

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