- 35 degrees C equals to what degree in Feirnhieght (Type an integer or decimal rounded to one decimal place as needed.)

In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=

just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}$ Given

$\displaystyle 2) \text{ } m \angle PAB = 60$ Definition of equilateral.

$3)\text{ } m \angle QAC = 60$ Definition of equilateral.

$4)\text{ } m\angle PAB = m\angle QAC$ Substitution

$5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC$ Angle Addition

$\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC$ Angle Addition

$7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC$ Substitution

$\displaystyle 8)\text{ } m\angle PAC=m\angle QAB$ Substitution

$9)\text{ } PA=BA$ Definition of equilateral

$10)\text{ } AC=AQ$ Definition of equilateral

$\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ$ Side-Angle-Side Congruence*

$\displaystyle 12)\text{ } PC=BQ$ CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

6 0

2 years ago

Read 2 more answers

M=3 and the y-intercept is (0,2)

andreev551 [17]

If you are asking for the formula thing, it is

y=3x+2

3 0

2 years ago

Use trig to find the legs of ABC if the base is AC and the height is BC (round to nearest tenth)

umka2103 [35]

Answer:

GIVEN :-

∠A = 15°
Length of AB (hypotenuse) = 60 ft

TO FIND :-

Length of BC
Length of AC
Area of ΔABC

FACTS TO KNOW BEFORE SOLVING :-

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$

SOLUTION :-

In ΔABC ,

$\sin 15 = \frac{BC}{60}$

$=> 0.2588... = \frac{BC}{60}$

$=> BC = (0.2588....) \times 60 = 15.5291.....$ ≈ 15.5 ft

$\cos 15 = \frac{AC}{60}$

$=> 0.9659..... = \frac{AC}{60}$

$=> AC = (0.9659.....) \times 60 = 57.9555.....$ ≈ 58 ft

Area of ΔABC = $\frac{1}{2} \times 58 \times 15.5 = 449.5 \:ft^2$

4 0

2 years ago

The graph H shows the height, in meters, of a

olga nikolaevna [1]

Answer:

a) H0 = 15 m, is the initial height, the height of the rocket at time 0 s.

b) $D=[0,5]$

c) $R=[0,35]$

Step-by-step explanation:

a) H0 is the initial height. It means the height of the rocket at time 0 s.

This value is 15 m.

b) The domain is all values of t between 0 and 5 seconds.

$D=[0,5]$

c) The range is all values of height from 0 to 35 meters.

$R=[0,35]$

I hope it helps you!

8 0

2 years ago

Use the distributive property to help you solve the equation. - 6(t + 2) = 18 t=

Ede4ka [16]

Answer:

t = -5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

-6(t + 2) = 18

Step 2: Solve for t

[Distributive Property] Distribute -6: -6t - 12 = 18
[Addition Property of Equality] Add 12 on both sides: -6t = 30
[Division Property of Equality] Divide -6 on both sides: t = -5

3 0

2 years ago

- 35 degrees C equals to what degree in Feirnhieght ​(Type an integer or decimal rounded to one decimal place as​ needed.)

- 35 degrees C equals to what degree in Feirnhieght (Type an integer or decimal rounded to one decimal place as needed.)