Answer:
C
Step-by-step explanation:
The sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 1 and d = 3, thus
= 1 + 3(n - 1) = 1 + 3n - 3 = 3n - 2 → C
<span>4^2 x 4^8 = 4^(2+8) = 4^10
hope it helps</span>
The <em>echo</em> number 20222022202220222022 is the <em>perfect</em> square of 4496890281.
<h3>What echo number is a perfect square</h3>
An <em>echo</em> number has a <em>perfect</em> square if its square root is also a <em>natural</em> number. After some iterations we found that <em>echo</em> number 20222022202220222022 is a <em>perfect</em> square:
The <em>echo</em> number 20222022202220222022 is the <em>perfect</em> square of 4496890281.
To learn more on natural numbers, we kindly invite to check this verified question: brainly.com/question/17429689
Answer:
y=32x-32
Step-by-step explanation:
this time no algorithm or equation was needed i saw that if the equation was y=32x there would be ordered pairs (1,32) and (2,64) so to delay it by 1 on the x side just subtract the slope from the y - intercept sorry if that doesn't make sense