Answer: Option (d) is the correct answer.
Explanation:
Carbon tetrachloride 
is a non-polar solvent. Whereas out of the given options, 
, 
, 
, and HI are all polar molecules.
On the other hand, only 
is non-polar molecule.
Also it is known that like dissolves like.
So, being non-polar 
will dissolve the give alkane, .
False.
Na does represent sodium, but NOT when it lost an electron. Na+ represents sdoium when it lost its electron.
Answer:
1)KNO3 ( pottasium trioxonitrate (V)
2)Ca(NO3)2 (calcium trioxonitrate (V
Explanation:
1)KNO3 ( pottasium trioxonitrate (V)
2)Ca(NO3)2 (calcium trioxonitrate (V)
Thses two compounds are metallic compounds and does not react with either the acid or the base.
Write the type of metal, based on your examination of the periodic table?
1)KNO3 ( pottasium trioxonitrate (V) have a potassium element which belongs to group 2 of the Periodic table which is an alkaline metal and can react with water or steàm
2)Ca(NO3)2 (calcium trioxonitrate (V) has calcium metal element which is an alkaline earth metal in the Periodic table and they react with Hallogens
Explanation:
When we move across a period from left to right then there will occur an increase in electronegativity and also there will occur an increase in non-metallic character of the elements.
As calcium (Ca) is a group 2A element and rubidium (Rb) is a group 1A element. Hence, Rb being an alkali metal is more metallic in nature than calcium (alkaline earth metal).
Both magnesium (Mg) and radium (Ra) are group 2A elements. And, when we move down a group then as the size of element increases so, it becomes easy of the metal atom to lose an electron.
As a result, there occurs an increase in metallic character of the element. Hence, Radium (Ra) is more metallic in nature than magnesium (Mg).
Also, both bromine and iodine are group 17 elements. Since, both of them are non-metals and non-metallic character increases on moving down the group.
Therefore, bromine (Br) is more metallic than iodine.
