Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
Answer:
-11/6
Step-by-step explanation:
Answer:
Your answer would be C: 4
Step-by-step explanation:
Well, I mean, 4 is greater than 3, but is less than 5. Which proves the n > 5 part wrong.
Answer:
No
Step-by-step explanation:
Let's find the slope of both lines and then compare these slopes:
From (-4,3) to (-5,4) entails a decrease of -1 in x and an increase of 1 in y. Thus, the slope is m = rise / run = 1/(-1) = -1.
From (0,1) to (5,0) entails an increase of 5 in x and a decrease of 1 in y. The slope here is m = rise / run = -1/5.
For these lines to be parallel, their slopes must be the same. That is not the case here, so NO, the lines are not parallel.
