Answer:
5.415m and 2.585m long
Step-by-step explanation:
For a right triangle
hyp^2 = opp^2 + adj^2 (Pythagoras theorem)
Given
hypotenuse = 6m
height(opposite) = h meters
Adjacent = (8-h)m
Substitute into the expression above;
6² = h²+(8-h)²
36 = h²+64-16h+h²
36 = 2h²-16h+64
2h²-16h+64-36 = 0
2h²-16h+28= 0
Divide through by 2
h²-8h+14 = 0
Using the general formula
h = 8±√8²-4(14)/2
h = 8±√64-56/2
h = 8±√8/2
h = 8±2.83/2
h = 8+2.83/2 and 8-2.83/2
h = 10.83/2 and 5.17/2
h = 5.415 and 2.585
hence the length of the height of the right triangle are 5.415m and 2.585m long
Answer: A) none of the equations are identities
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Part 1
Plug in theta = 0
sin(theta+pi/2) - cos(theta+pi/6) = 2*cos(theta) - sin(theta)
sin(0+pi/2) - cos(0+pi/6) = 2*cos(0) - sin(0)
1 - sqrt(3)/2 = 2*1 - 0
0.13 = 2
which is a false equation
So we do not have an identity in equation 1.
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Part 2
Plug in theta = 0
sin(theta+pi/6) + cos(theta+pi/3) = (sqrt(2)/3)*sin(theta) + 2*cos(theta)
sin(0+pi/6) + cos(0+pi/3) = (sqrt(2)/3)*sin(0) + 2*cos(0)
1/2 + 1/2 = 0 + 2
1 = 2
which is also false
This is not an identity either.
Answer:
F =
Step-by-step explanation:
Given
C = ( multiply both sides by 9 to clear the fraction )
9C = 5(F - 32) ← distribute
9C = 5F - 160 ( add 160 to both sides )
9C + 160 = 5F ( divide both sides by 5 )
= F