Answer:
3a) The value of x = 56
3b) The measure of ∠ H T M = 90°
3c) The radius of the circle = 53
Step-by-step explanation:
3a) ∵ A F is a tangent to the circle O at point F
∵ Secant AH intersects circle O at point T
∴ (A F)² = (A T)(A H)
∴ 7( x + 7) = (21)² ⇒ ÷ 7
∴ x + 7 = 63
∴ x = 63 - 7 = 56
3b) ∵ HM is a diameter
∴ The measure of the arc HM = 180° ⇒ semi-circle
∵ ∠ H T M is inscribed angle subtended by the arc HM
∴ m ∠ H T M = half the measure of arc HM
∴ m ∠ H T M = 180° ÷ 2 = 90°
3c) ∵ Δ H T M is a right angle triangle at T
∴ (H M)² = (M T)² + (H T)² ⇒ Pythagorean theorem
∴ (H M)² = (90)² + (56)²
∴ (H M)² = 11236
∴ HM = 
= 106
∴ OM = 106 ÷ 2 = 53
∵ OM is the radius of the circle O
∴ The radius = 53
Answer:
The answer is 'The slope of g(x) is less than the slope of f(x)'
Step-by-step explanation:
Given the graphs of f(x) and g(x). we have to compare the slops of these two.
The graph of f(x) passes through the points (1,0) and (2,2)
∴ 
The graph of g(x) passes through the points (0,2) and (2,3)
∴ 
As 
This shows that the
The slope of g(x) is less than the slope of f(x).
Answer:
12x-6
Step-by-step explanation:
perimeter= 2l+2w
=2(x+4)+2(5x-7)
=2x+8+10x-14
=12x-6
Answer:
4/-2
Step-by-step explanation:
Start at a point where the line intersects a firm coordinate like y=2 then use rise/run rise is vertical and run is horizontal count from the intersection up to where the line intersects another firm point in this case y=6 then count the run which lands on x=-2 y=6 which gives you the slope of 4/-2
