Answer:
a)
b)
And replacing we got:
c)
d)
e)
f)
And replacing we got:
And the variance would be:
And the deviation:
Step-by-step explanation:
We have the following distribution
x 0 1 2 3 4
P(x) 0.2 0.3 0.1 0.1 0.3
Part a
For this case:
Part b
We want this probability:
And replacing we got:
Part c
For this case we want this probability:
Part d
Part e
We can find the mean with this formula:
And replacing we got:
Part f
We can find the second moment with this formula
And replacing we got:
And the variance would be:
And the deviation:
Answer
Good morning, I loveeeee FRIDAYSSSSS!!!!
Step-by-step explanation:
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
You can draw vertical line, and get 2 rectangles.
1) First one with sides 2 and 7.
2) Second one with sides 1 and (5-2) = 3, 1 and 3.
3) Area of the first one =2*7=14 units²
4)Area of the second one = 1*3=3 units²
5) Area of the whole polygon = 14+3=17 units²
Answer C. 17units².