The formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1. as shown below:
<h3>What is the equation of the formation of ammonia?</h3>
Ammonia gas is formed from the reaction between nitrogen gas and hydrogen gas.
Three moles of hydrogen gas will react with 1 mole of nitrogen gas to form 2 moles of ammonia gas.
The equation of the reaction is given below as:
Therefore, the formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1.
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This equation represents a single replacement reaction. Single replacement reactions consist of one element reacting with one compound on the reactant side (left side of the equation) and they form one new element and one new compound on the product side of the equation (right side).
0.115 M means that 0.115 moles of KBr are contained in a volume of 1000 ml, therefore a volume of 350 ml will have (0.115 × 0.35) = 04025 moles
From the formula of molarity moles = molarity × volume in liters
1 mole of KBr is equivalent to 119 g
Therefore, the mass = 0.04025 × 119 g = 4.79 g