Answer:
Step-by-step explanation:
Since the amplitude of the cosine function is 2, I would put the multiply it by 2. There is no phase shift
The period is 1/2, so it would be 4pi
Plug them in into y=Acos(Bx), y=2cos(4pix)
Answer:
9pr = 2q^2
Step-by-step explanation:
28.
px^2 + qx + r = 0
If one root is A then the other root is 2A
We have A + 2A = -q/p and A*2A = r/p
So 3A = -q/p so A = -q/3p and A^2 = r/2p so A = √ (r / 2p)
Equating these 2 equations:-
-q/3p = √(r / 2p)
q^2 / 9p^2 = r / 2p
9p^2r = 2pq^2
9pr = 2q^2 (answer)
Yesterday.
Exp: if you make the denominators equal, 5/6 becomes 10/12 which is more than 7/12
Y2-y1/x2-x1 is slope so
9-9/14-(-20) so you get 0/34 which means there is no slope since they have the same y (the equation would be y=0x+9 therefore y=9)
Which makes sense since the equation is a straight line
The answer to this question is 15
