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2 years ago

900n pushes a wedge 0.10 m into a log, if the work done on the log is 50j what is the efficiency of the wedge

Physics

1 answer:

mariarad [96]2 years ago

7 0

Answer:

100

Explanation:

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Kristen has two identical sized cubes, one is lead (Pb) and one is copper (Cu). Kristen is determining the density of each cube.

natta225 [31]

Answer:

volume

Explanation:

Identical size means volume will be the same in each calculation of

density = mass / <u>volume</u>

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1 year ago

Two rocks are moving through empty space in a straight line at the same speed. One has a mass of 10 kg, the other has a mass of

Yuki888 [10]

A and D are definitely wrong because the two rocks have different masses, so it leaves us with B and C. The most logical answer to the question is
C <span>The one with greater mass takes more force to stop.
</span>

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2 years ago

A long thin rod of mass M and length L is situated along the y axis with one end at the origin. A small spherical mass m1 is pla

Yuri [45]

Answer:

$= - 5.65\times 10^{-2} J$

Explanation:

Given data:

L =2.00 *10^4 m

d = 18*10^4 m

M = 18 *10^6 kg

m_1 = 8*10^6 kg

Gravitational energy is given as

$U =- G \frac{m_1 m_2}{r}$

mass per unit length is given as

$\sigma = \frac{M}{L} = \frac{18 \times 10^6}{2\times 10^4 m} = 900 kg/m$

calculating potential energy

$dU ==-G\int_{16\times 10^4}^{18\times 10^4} \frac{m_1 *dm}{r}$

$=-G\int_{16\times 10^4}^{18\times 10^4} \frac{m_1 *\sigma dr}{r}$

$=-G*m_1*\sigma\int_{16\times 10^4}^{18\times 10^4} \frac{dr}{r}$

$=-G*m_1*\sigma \left | ln r \right |_{16\times 10^4}^{18\times 10^4}$

$=-G*m_1*\sigma ln(1.125)$

$=-6.673 \times 10^{-11}*8*10^6*900*ln(1.125)$

$= - 5.65\times 10^{-2} J$

5 0

2 years ago

Jennifer, who has a mass of 48.0 kg, is riding at 40.2 m/s in her red sports car when she must suddenly slam on the brakes. An a

Bogdan [553]

Answer:

$F = 3445.714\,N$

Explanation:

The system can be modelled appropriately by the use of the Principle of Momentum Conservation and Impact Theorem:

$(48\,kg)\cdot (40.2\,\frac{m}{s} ) - F\cdot (0.56\,s) = 0\,\frac{kg\cdot m}{s}$

The average force exerted on her:

$F = 3445.714\,N$

3 0

2 years ago

Read 2 more answers

6. What is the resultant force on each car below? Remember TWO pieces of

tamaranim1 [39]

Explanation:

In first case, the forces on LHS and on RHS is the same i.e. 3 N. The force acting on the car is balanced force. As a result, the car will not move at all.

In second case,

Force on RHS = 2000 N

Force on LHS = -6000 N

Net force acting on it is given by :

F = 2000+(-6000)

= -4000 N

Hence, this is the required solution.

4 0

2 years ago