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2 years ago

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Estimate the time Juanita will arrive at her aunt's home 320 miles away if she leaves at 9:00 a.m., drives about 60 miles per ho

ur, and stops
for a 40 minute break halfway.

A 12:00 p.m.

B. 1:00 p.m.

c. 2:00 p.m.

D. 3:00 p.m.

E. 4:00 p.m.

1 answer:

uranmaximum [27]2 years ago

4 0

Answer:

D. 3:00 p.m.

Step-by-step explanation:

d = Distance = 320 miles

s = Speed = $60\ \text{mph}=\dfrac{60}{3600}=\dfrac{1}{60}\ \text{miles/s}$

Time taken is given by

$t=\dfrac{d}{s}\\\Rightarrow t=\dfrac{320}{\dfrac{1}{60}}\\\Rightarrow t=19200\ \text{s}$

40 minutes break is $40\times 60=2400\ \text{s}$

Total time taken is $19200+2400=21600\ \text{s}=\dfrac{21600}{60\times 60}=6\ \text{hours}$ .

So, the entire trip took 6 hours. 6 hours after 9 a.m. is 3 p.m.

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Answer:

6546 students would need to be sampled.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

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The margin of error is:

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So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?

n students would need to be sampled, and n is found when M = 0.01. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.645\sqrt{\frac{0.59*0.41}{n}}$

$0.01\sqrt{n} = 1.645\sqrt{0.59*0.41}$

$\sqrt{n} = \frac{1.645\sqrt{0.59*0.41}}{0.01}$

$(\sqrt{n})^2 = (\frac{1.645\sqrt{0.59*0.41}}{0.01})^2$

$n = 6545.9$

Rounding up:

6546 students would need to be sampled.

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2 years ago

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1 year ago

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2 years ago

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kotegsom [21]

Answer:

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Step-by-step explanation:

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Substituting the known 'x', and 'y', values for the coordinates of the points, we have;

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