10 families were asked how many pets they have.here i8s the data.2,3,3,5,4,2,4,0,1,3 find the mean ,medianand mode of the data?
VladimirAG [237]
The mean is 2.7.
The median is: 3
The mode is 3.
Hope this helps!
pls give Brainliest answer!
p.s. if you need an explanation of how to find the mean, median, and mode, just pm me.
Commission earned by William is $ 45.84
<h3><u>
Solution:</u></h3>
Given that,
William makes a commission of 6% percent on everything he sells
He sells a computer for $764.00
<em><u>To find: Commission amount of William</u></em>
Given that he makes a commission of 6 % on everything he sells. So he has received a commission of 6 % of $ 764.00
Commission amount of William = 6 % of $ 764.00
a % of b can be written in fraction as
Thus commission earned by William is $ 45.84
Answer:
5
Step-by-step explanation:
Answer:
There are 9 dots. So 9.
Step-by-step explanation:
Just take my word for it.
Let's say that in the beginning he weighted x and at the end he weighted x-y, y being the number of kg he wanted to loose.
first month he lost
y/3
then he lost:
(y-y/3)/3
this is
(2/3y)/3=2/9y
explanation: ((y-y/3) is what he still needed to loose: y minus what he lost already
and then he lost
(y-2/9y-1/3y)/3+3 (the +3 is his additional 3 pounts)
(y-2/9y-1/3y)/3-3=(7/9y-3/9y)/3+3=4/27y+3
it's not just y/3 because each month he lost one third of what the needed to loose at the current time, not in totatl
and the weight at the end of the 3 months was still x-y+3, 3 pounds over his goal weight!
so: x -y/3-2/9y-4/27y-3=x-y+3
we can subtract x from both sides:
-y/3-2/9y-4/27y-3=-y+3
add everything up:
-19/27y=-y+6
which means
-19/27y=-y+6
y-6=19/27y
8/27y=6
4/27y=3
y=20.25
so... that's how much he wanted to loose, but he lost 3 less than that, so 23.25
ps. i hope I didn't make a mistake in counting, let me know if i did. In any case you know HOW to solve it now, try to do the calculations yourself to see if they're correct!