Ralph chase invested $85000 at an interest of 10% and $70000 at an interest of 8%
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.
Let a represent the amount invested at interest of 10% and b represent the amount invested at 8%, hence:
a + b = 155000 (1)
Also:
0.1a + 0.08b = 14100 (2)
From both equations:
a = 85000, b = 70000
Ralph chase invested $85000 at an interest of 10% and $70000 at an interest of 8%
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Answer:
Play 3
Step-by-step explanation:
Given:
Required [Missing from the question]:
Determine the play with the least change in yard?
To do this, we ignore the sign in front of each yard before we analyze.
So, we have:
Play 1 has a change of 4
Play 2 has 6
Play 3 has 2
Play 4 has 3
<em>From the above analysis, play has the least (which is 2)</em>
Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
Answer:
9 square units
Step-by-step explanation:
