False. At equilibrium, the rate of forward reaction is equal to the rate of backward reaction. The net concentration of both products and reactants won't change, but the reactions still take place.
Aluminum foil I think but if not goodluck :)
If you mean hydrate as in <em>MgSO4 · 7H2O, </em>then simply find the molar mass of each element you see.
For the example above, that means you would add the molar mass (found on the periodic table) of Mg, then S, then 4(O), 14(H), and 7(O).
The results would be your molar mass for the hydrate.
I hope this is what you meant by your question!
Answer:
Option C = 6 of carbon react with 16 g of oxygen.
Explanation:
In given question it is stated that 12 g of carbon react with 32 g of oxygen to produce carbon dioxide. The other combination option c is also true because in this, the quantity of both reactant is just half from the given quantity. Which means that if 100 % product is obtained from the 12 g of carbon and 32 g of oxygen then by taking the half amount of reactant the product will be half i.e 50% .
This combination is true because the ratio of both reactant are justified.
Carbon 12g + Oxygen 32g → carbon dioxide
C : O 1 : 2.6
Option C:
Carbon ( 12/2 =6g ) + Oxygen (32/2 = 16g) → Carbon dioxide
C : O 1 : 2.6
