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2 years ago

10

The school carnival has a booth of where people can win prizes by guessing the correct number of items in different sized jars j

ust by looking at them. Jessica really wants the cylinder shaped jar full of sour jawbreakers. What would get her closest to the correct number of jawbreakers without being disqualified from the contest?

1 answer:

aalyn [17]2 years ago

5 0

Answer:

D

Step-by-step explanation:

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Matthew and Kobie both want to do a survey to determine how many people in their community might have the Corona 19 Virus. Which

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2 years ago

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HELP ME PLEASEEEE

dmitriy555 [2]

Answer: 5/4 = 1 2/8

Step-by-step explanation: That's the answer

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1 year ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

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3 years ago

A farmer uses 3/5 of his land to grow cassava, 1/3 of the remainder for yam and the rest for maize. Find the part of the land us

alexira [117]

Answer:

Step-by-step explanation:

Cassava = 1/3 of his land

Remaining after planting Cassava = 1 - 1/3 = 2/3 of his land

Maize = 2/5 x 2/3 = 4/15 of his land

Vegetables = 2/3 - 4/15 = 2/5 of his land

If vegetables = 10 acres

2/5 of his land = 10 acres

1/5 of his land = 10 ÷ 2 = 5 acres

5/5 of his land = 5 x 5 = 25 acres

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2 years ago

Find the distance between the two points rounding to the nearest tenth (if necessary). (2,−3) and (0,−8)

saveliy_v [14]

Answer:

square root of 29

Step-by-step explanation:

use the distance formula and then plug the numbers in, i got the sqrt(29) after i did that

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2 years ago