2 years ago

I need someone to talk to... im at school bored

Mathematics

1 answer:

balu736 [363]2 years ago

8 0

Answer:

sure

Step-by-step explanation:

You might be interested in

Which of the equations listed below are linear equations?

telo118 [61]

Answer:

iK ITS A TRICKY QUESTION ITS C THOUGH

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$