Answer:
(f + g)(x) = x^2 + 3x - 6
Step-by-step explanation:
Given f(x) = x^2 + x − 2 and g(x) = 2x − 4
Plug in:
(f + g)(x) = x^2 + x − 2 + 2x − 4
(f + g)(x) = x^2 + 3x - 6
38 10 49 11 60 12..
How
27 - 16 = 11
8 - 7 = 1
So for each small number add 1 ad for the big add 11
Easy the answer is B: 17 and one-third
W=A\L
Divide L from both sides
The L in the right cancels out