Given:
In circle O, m∠R = 30.8°.
To find:
The m∠NOQ
Solution:
Central angle theorem: According to this theorem, the central angle is always twice of subtended angle on the same arc.
Angle NOQ and angle NRQ are on the same arc but ∠NOQ is the central angle and ∠NRQ is the subtended angle on the arc NQ.
Using central angle theorem, we get
Therefore, .
Answer:
x = 3.3 and -0.3
Step-by-step explanation:
Given the expression
1/x-4 + x/x-2=2/x^2-6x+8
Find the LCM
x-2+x(x-4)/(x-4)(x-2) = 2/x^2-6x+8
Since the denominator, are the same they cancels out
x +1 + x(x-4) = 2
x+1 + x²-4x = 2
x²-3x + 1 - 2 = 0
x² - 3x - 1 = 0
Factorize
x =3±√9+4/2
x =3±√13/2
x = 3±3.6/2
x= 6.6/2 and -0.6/2
x = 3.3 and -0.3
Answer:
5 & 1
Step-by-step explanation:
We can use the quadratic formula to solve this:
Quadratic Formula = 
So we will have 2 answers (roots).
a is the coefficient of x^2 (2)
b is the coefficient of x (-12)
c is the constant (10)
Now, substituting, we get:
x = 
Hence the roots are 5 & 1
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