The "I"'s r variables, now u do 2-5 which sequels -2. now u do 4+7 and that ='s 11. now I think u take 11 and -2 and u subtract 11-(-2). or it could be change the negative into a positive and add them together.
There are 10,000 total four-digit numbers (1000 through 9999).
Multiples of 2 end in 0, 2, 4, 6, and 8. There are 9*10*10*5 = 4500 four-digit multiples of 2.
Multiples of 5 end in 0 or 5. There are 9*10*10*2 = 1800 four-digit multiples of 5.
There is redundancy between the two sets of numbers, namely those that end in 0, which are both multiples of 2 and 5. There are 9*10*10*1 = 900 four-digit multiples of both 2 and 5.
Then there are 4500 + 1800 - 900 = 5400 total four-digit numbers that are either multiples of 2 or 5, which means the remaining 4600 numbers are neither multiples of 2 nor 5.
The answer is i don’t know or I don’t care and what are we trying to find
It’s 5,905 bc you need to add all of you distilled water to know if you have enough