How many moles of oxygen atoms are present in 5
moles of Mg3(PO4)2
All you have to do is to create
a ratio between the molecule and the oxygen atom.
5 moles of Mg3(PO4)2 (4x2 moles
O/1 mole Mg3(PO4)2) = 40 moles of oxygen
1) Find the number of moles that the final solution must contain
M = n / liters of solution => n = M*liters of solution
n = 1.5 mol/liter * 25.0 liter = 37.5 moles
2) Find how many liters of the stock solution contain 37.5 moles of HCL
M = n / liters of sulution => liters of solution = n / M = 37.5 mol / 18.5 mol/liter
liter of solution = 2.03 liter
Answer: 2.03 liter
Answer:
0.2 M
Explanation:
Step 1: Given data
- Mass of sugar (sucrose): 15 g
- Volume of water: 0.2 L (we will assume it is the volume of the solution)
There are different ways to express the concentration of a solution. We will calculate molarity, which is one of the most used.
Step 2: Calculate the moles of sucrose
The molar mass of sucrose is 342.3 g/mol.
15 g × 1 mol/342.3 g = 0.044 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.044 mol/0.2 L = 0.2 M