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2 years ago

What is the simplified expression for 3^3• 3^3/3^4?A. 3^0B.3^1C.3^2D.3^4

Mathematics

2 answers:

Klio2033 [76]2 years ago

8 0

Answer:

Step-by-step explanation:

It is C because multiplying exponents means you add the top number while dividing means subtract.

Andreyy892 years ago

4 0

Answer:

Its C

Step-by-step explanation:

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Find four consecutive natural numbers if you know that the product of the first two is 38 less than the product of the following

Fynjy0 [20]

<span>Because the four numbers are consecutive, we can call the first one x, and the other three are x+1, x+2, and x+3, respectively. x * (x+1) = (x+2) * (x+3) - 38 x^2 + x = x^2 + 5x +6-38 x^2 + x = x^2 + 5x - 32 -4x = -32 x=8 The four numbers are 8, 9, 10, and 11 check solution: 8*9=10*11-38 72=110-38 72=72</span>

8 0

2 years ago

Read 2 more answers

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

4/9 as decimal show your work

Fed [463]

4/9

= 0.44444444

= Rounded to 0.44

The correct answer is 0.44

4 0

2 years ago

Read 2 more answers

What is the scale factor, perimeter ratio, surface ratio, and the volume ratio?????????????????????????????

tamaranim1 [39]

Answer:

Scale factor = $\frac{4}{9}$

Perimeter ratio = 4 : 9

Surface area ratio = 16 : 81

Volume ratio = 64 : 729

Step-by-step explanation:

Volume ratio = $\frac{\text{volume of small prism}}{\text{Volume of large prism}}$

= $\frac{128}{1458}$

= $\frac{64}{729}$

= 64 : 729

Scale factor = $\sqrt[3]{\frac{\text{volume of small prism}}{\text{Volume of large prism}}}$

= $\sqrt[3]{\frac{64}{729}}$

= $\frac{4}{9}$

Perimeter ratio = Scale factor

= $\frac{4}{9}$

= 4 : 9

Surface area ratio = (Scale factor)²

= $(\frac{4}{9})^{2}$

= $\frac{16}{81}$

= 16 : 81

3 0

2 years ago

What is the coefficient of y in the expression 2 ⋅ 4 + 3y?

svet-max [94.6K]

A coefficient is the number that is multiplied by the variable (the letter).
so the coefficient in ur expression is 3.

the 2 and the 4 are constants...because they are numbers with no variables

5 0

2 years ago

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What is the simplified expression for 3^3• 3^3/3^4?A. 3^0B.3^1C.3^2D.3^4​

What is the simplified expression for 3^3• 3^3/3^4?A. 3^0B.3^1C.3^2D.3^4