Answer:
Step-by-step explanation:
The parent function here is y = log x, where 10 is the base.
The derivative of y = log x is dy/dx = (ln x) / ln 10.
The derivative of y = log (ax+b) is found in that manner, but additional steps are necessary: differentiate the argument ax + b:
The derivative with respect to 10 of log (ax + b) is:
dy/dx = [ 1 / (ax + b) ] / [ ln 10 ] *a, where a is the derivative of (ax + b).
Alternatively, we could express the answer as
dy/dx = [ a / (ax + b) ] / [ ln 10 ]
Answer:4.3
You round to the tenths place
Answer:
Don't worry Its a
Step-by-step explanation:
Answer: (f-g)(2)=14
Step-by-step explanation:
(f – g) (-2) means the same as subtracting f(2) and g(2). Since we are given f(x) and g(x), we can use them to solve. There are two ways to solve. One is to find f(2) and g(2), and then subtract them. Another way is to do (f-g)(x), then plug in x=2. I will show both methods.
Method 1
f(2)=3(2)²+1 [exponent]
f(2)=3(4)+1 [multiply]
f(2)=12+1 [add]
f(2)=13
g(2)=1-(2) [subtract]
g(2)=-1
(f-g)(2)=13-(-1) [subtract f(2) and g(2)]
(f-g)(2)=14
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Method 2
(f-g)(x)=3x²+1-(1-x) [distribute -1]
(f-g)(x)=3x²+1-1+x [combine like terms]
(f-g)(x)=3x²+x
(f-g)(2)=3(2)²+2 [plug in x=2, exponent]
(f-g)(2)=3(4)+2 [multiply]
(f-g)(2)=12+2 [add]
(f-g)(2)=14
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Now, we know that (f-g)(2)=14. We confirmed this with both methods.
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