Answer:
k =
Step-by-step explanation:
Fisherman noticed a stretch in the spring = 'b' centimetres
Weight of the fish = a kilograms
If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,
F = kΔx
Where k = spring constant
Δx = stretch in the spring
F = weight applied
F = mg
Here 'm' = mass of the fish
g = gravitational constant
F = a(9.8)
= 9.8a
Δx = b centimetres = 0.01b meters
Therefore, 9.8a = k(0.01b)
k =
k =
Therefore, spring constant of the spring will be determined by the expression, k =
Answer:
I believe the answer is 3/7. Hope this helps!
Step-by-step explanation:
Answer:
Step-by-step explanation:
strategy: find the distance of the two points, take half of that, b/c that will be the radius, Then use the area of a circle formula to find the answer
P1 = (1,-1) in the form (x1,y1)
P2= ((3,3) in the form (x2,y2)
dist = sqrt [ (x2-x1)^2 + (y2-y1)^2 ]
dist = sqrt [ 3 -1 )^2 + 3-(-1)^2 ]
dist = sqrt [ 2^2 + 4^2 ]
dist = sqrt [ 4 + 16 ]
dist = sqrt [20]
r = /2
area of circle =
area of circle = ( /2)^2
area of circle = ( /2)( /2)
area of circle = (20 / 4)
area of circle = 5
area of circle = 5
It is 8.5, how you get it is simple. (Divide 102 by 24, then add 4.25 to that answer)