Answer:
77 moles
Explanation:
The given chemical compound is CCl2F2 is called Dichlorodifluoromethane. In CCl2F2, we have:
one mole of a Carbon atom.
two moles of Chlorine atom; &
two moles of Fluorine atom.
Given that one mole of Chlorine = 38.5 moles.
Then, two moles will be:
= 2 × 38.5 moles
= 77 moles
Answer:
O=O bond
Explanation:-
Note it down that the bond having highest Hydrogen enthalpy has strongest bond.
Now
- O=O(495KJ/mol)
- O-O(146KJ/mol)
- O-H(467KJ/mol)
- H-H(432KJ/mol)
Hence
Answer:
Ammonia > Urea > Ammonium nitrate > Ammonium sulphate
Explanation:
Percentage by mass of nitrogen in NH3:
Molar mass of NH3= 17 g/mol
Hence % by mass = 14/17 × 100 = 82.35%
% by mass of NH4NO3
Molar mass of NH4NO3 = 80.043 g/mol
Hence; 28/80.043 × 100 = 34.98%
% by mass of (NH4)2SO4;
Molar mass of (NH4)2SO4= 132.14 g/mol
Hence; 28/132.14 × 100 = 21.19%
% by mass of CH4N2O
Molar mass of urea = 60.0553 g/mol
Hence 28/60.0553 × 100 = 46.62%
Answer:
1.26 × 10^-8 M
Explanation:
We are given;
Number of moles of mercury (i) chloride as 0.000126 μmol
Volume is 100 mL
We are required to calculate the concentration of the solution.
We need to know that;
Concentration is also known as molarity is given by;
Molarity = Number of moles ÷ Volume
Number of moles = 1.26 × 10^-10 Moles
Volume = 0.01 L
Therefore;
Concentration = 1.26 × 10^-10 Moles ÷ 0.01 L
= 1.26 × 10^-8 M
Thus, the molarity of the solution is 1.26 × 10^-8 M