Answer:
The horizontal component of the vector ≈ -16.06
The vertical component of the vector ≈ 19.15
Explanation:
The magnitude of the vector, = 25 units
The direction of the vector, θ = 130°
Therefore, we have;
The horizontal component of the vector, Rₓ = × cos(θ)
∴ Rₓ = 25 × cos(130°) ≈ -16.06
<em>The horizontal component of the vector, Rₓ ≈ -16.06</em>
The vertical component of the vector, R = × sin(θ)
∴ R = 25 × sin(130°) ≈ 19.15
<em>The vertical component of the vector, R</em><em> ≈ 19.15</em>
(The vector, R = Rₓ + R
= Rₓ·i + R·j
∴ ≈ -16.07·i + 19.15j)