−5x−1= \,\,-2x+14 −2x+14

Mathematics

1 answer:

Scilla [17]2 years ago

3 0

Answer:

yeaa this is hard but i will help u if i knew what the answer was srry ma g

Step-by-step explanation:

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Please help! I attached the question below.

kompoz [17]

Answer:

$\frac{2(c+2)}{c(c-2)}$

Step-by-step explanation:

$\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }$

Identity used:

$a^{2}-b^{2}=(a-b)(a+b)$

$\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }$

Now let us divide the modified expressions:

$\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})}$ ÷ $\frac{(c-2)^2}{2(6c^{3}+15c^{2}) }$

we get:

$\frac{2(c+2)}{c(c-2)}$

5 0

2 years ago

A soccer team wins 65% of its matches, and 15% of its matches end in a draw. If the team is scheduled to play 20 matches, about

Finger [1]

The team plays 20 matches.

65% of the matches, the teams wins
= 20 * 0.65
= 13 matches

15% of the matches, the games ends in draw.
= 20 * 0.15
= 3 matches

The team is expected to lose in
= 20 - 13 - 3
= 4 matches

3 0

2 years ago

PLEASE HELPP I AM FAILING AND I NEED THIS ASAP!!! TYSM

Lana71 [14]

Answer:

See below for answers

Step-by-step explanation:

Do you mean $f(x)=2sin(x-1)$ or $f(x)=2sin(x) -1$ ?

Use the formula $f(x)=asin(bx+c)+d$ where $|a|$ is the amplitude, $-\frac{c}{b}$ is the phase shift, $d$ is the vertical shift, and the period is $\frac{2\pi}{|b|}$ .

Assuming your first case is true, the amplitude would be $|a|=|2|=2$ , your period is $\frac{2\pi}{|1|}=2\pi$ , and your midline/vertical shift is $d=0$ .