Part A
The first thing we must do in this case is to hide the slopes of each line.
line m:
m = (- 4-3) / (0 - (- 4))
m = -7 / 4
Line n:
n = (- 2-2) / (3-1)
n = -4 / 2
n = -2
Answer:
Lines m and n are not parallel because their slopes are different.
Part B:
We look for the slope of the K line:
k = (1 - (- 3)) / (4 - (- 3))
k = 4/7
We observe that it is true that:
k = -1 / m
Answer:
The lines are perpendicular.
1 kg=1000g*1000mg/1g=1000000mg =10⁶ mg
or you can use proportion
1000g - x mg
1 g -1000mg
x=1000*1000=1000000mg
1kg=10⁶ mg
Answer: x=-10, y=13
Step-by-step explanation:
+2y-2y = 0, eliminating y is much easier. So -3x-5x = -8x and 56+24 = 80
Substitute x in any equations but only 1 equation (Don't substitute in both equations.)
For me, I'd substitute x in -3x+2y=50
So the answer is x = -10, y = 13
Answer:
Let's define the high temperature as T.
We know that:
"four times T, was more than 2*T plus 66°C"
(i assume that the temperature is in °C)
We can write this inequality as:
4*T > 2*T + 66°C
Now we just need to solve this for T.
subtracting 2*T in both sides, we get:
4*T - 2*T > 2*T + 66°C - 2*T
2*T > 66°C
Now we can divide both sides by 2:
2*T/2 > 66°C/2
T > 33°C
So T was larger than 33°C
Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.
Then the range of possible temperatures is:
(33°C, ...)
Where we do not have an upper limit, so we could write this as:
(33°C, ∞°C)
(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)
Answer:
\left(\frac{\sqrt{78}}{30},\ \frac{\sqrt{78}}{39}\ ,\frac{41\sqrt{78}}{390}\right)
