Answer:
Height, H = 25.04 meters
Explanation:
Initially the ball is at rest, u = 0
Time taken to fall to the ground, t = 2.261 s
Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :
Here, a = g
H = 25.04 meters
So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.
Answer:
Could you explain that more better?
Explanation:
1 foot = 30.48 cm
(x900) (x900)
900 feet = 27432 cm
Pls give me a brainliest if this helped thx
Answer:
U² = 142.86 N
U¹ = 357.14 N
Explanation:
Taking summation of the moment about point A, we get the following equilibrium equation: (taking clockwise direction as positive)
where,
W = weight of boy = 500 N
U² = reaction ay B = ?
Therefore,
<u>U² = 142.86 N</u>
Now, taking summation of forces on the plank. Taking upward direction as positive, for equilibrium position:
<u>U¹ = 357.14 N</u>
Answer:11
Explanation: because is the number that repeted 2 times