Ethyne also known as Acetylene and is the simplest Alkyne belonging to Unsaturated Hydrocarbons. It contains triple bond between two carbon atoms in a molecule. Carbon atoms in Acetylene are sp Hybridized and has a linear shape with bond angle of 180° is present between C-C-H bonds. This compound is also called as Binary Compound because it is made up of two elements i.e. Carbon and Hydrogen. The terminal Hydrogen in Acetylene is slightly Acidic in nature, and this compound can donate terminal proton to any strong base. These compounds generally give Electrophillic Addition Reactions.
Heat energy is absorbed by the substance.
We're given the [OH⁻] as 8.34 × 10⁻¹² M. Using the formula pOH = -log[OH⁻], the pOH of this solution would be -log(8.34 × 10⁻¹²) ≈ 11.08.
The pOH is, for lack of a better term, the "opposite" of pH: A pOH of 7 is neutral; a pOH less than 7 is <em>basic</em>; and a pOH greater than 7 is <em>acidic</em>.
This follows from the relation, pH + pOH = 14. In this case, with a pOH of 11.08, our pH would be 14 - 11.08 = 2.92, which is acidic (pH < 7).
Thus, the correct answer choice is B.
Answer:
Enthalpy of a reaction = P - R
Synthesis: ΔH = 25 kJ - (-30 kJ) = 55 kJ
Single Replacement: ΔH = 30kJ - 65 kJ = -35 kJ
Double Replacement: ΔH = 60 kJ - 10 kJ = 50 kJ
Explanation: