What has an atomic number of 1

Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(

likoan [24]

Balanced Half reactions are:

At anode 2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$

At Cathode: 2 $H^{+}$ + $2e^{-}$ ==> H₂

Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O, $H^{+}$ , $Mn^{2+}$ and $Cl^{-}$

Now at Anode reaction will occur as given:

2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$ (will occur)

At Cathode:

2 $H^{+}$ + $2e^{-}$ ==> H₂ (will occur)

At Cathode:

$Mn^{2+}$ + $2e^{-}$ ==> Mn (This reaction will not occur)

The deposition of solid Mn will not occur because in aqueous solution, $H^{+}$ will be reduced before $Mn^{2+}$ .

The reduction potentials for $H^{+}$ is zero whereas reduction potential for $Mn^{2+}$ is - 1.18V.

The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.

To learn more about the half reaction please click on the link brainly.com/question/13186640

#SPJ4

8 0

11 months ago

Write a balanced equation for the complete combustion of propane, C3H8 . Do not enter phase symbols. Enter the alkane formula as

Anastaziya [24]

Answer:

C3H8 + 5O2 => 3CO2 + 4H2O

Explanation:

Hydrocarbon combustion is the reaction between a hydrocarbon and O2 producing CO2 and water.

C3H8 + O2 => CO2 + H2O

First we balance the C and H.

C3H8 + O2 => 3CO2 + 4H2O

Now we balance O for the answer!

C3H8 + 5O2 => 3CO2 + 4H2O

3 0

2 years ago

What are humic acids?

Dominik [7]

Answer:

Los ácidos húmicos son restos de vida orgánica totalmente descompuestos. Son moléculas de cadena larga que son de alto peso y de color marrón oscuro. No son un solo ácido. Más bien, "ácido húmico" es un término amplio que se refiere a una mezcla compleja de muchos ácidos diferentes que son solubles en soluciones alcalinas. Existen de forma natural como parte del ciclo de vida de la naturaleza en suelos, océanos y arroyos. Cómo se forman?

Cuando las plantas y los animales mueren, sus moléculas quedan disponibles en el suelo para ser utilizadas por otros organismos. Bacterias, hongos, protozoos, lombrices de tierra e incluso insectos consumen el material fresco. Después de largos períodos de tiempo, cuando la materia en descomposición se ha comido y transformado a través de varios ciclos, lo que queda es un material resistente que resiste una mayor descomposición, llamado humus. (Este proceso se conoce como "humificación"). El humus es un término general que se refiere a compuestos estables y altamente complejos que son resistentes a una mayor descomposición. Y el humus consta de tres componentes: ácidos húmicos, ácidos fúlvicos y humus. Los ácidos húmicos y fúlvicos han demostrado ser invaluables para entornos de suelo saludables, particularmente por sus contribuciones a la estructura del suelo y la transferencia de nutrientes entre el suelo y las plantas.

5 0

2 years ago

Assuming that seawater is a 3.50 mass % aqueous solution of NaCl, what is the molality of seawater?

Fantom [35]

Hey there!

Consider 100 g of solution:

Mass of NaCl = 3.50% of mass of seawater

( 3.50 / 100 ) * 100 => 3.50 g

Number of moles as shown below:

Molar mass NaCl = 58.44 g/mol

n = Mass / molar mass

n = 3.50 / 58.44 => 0.059 moles of NaCl

Mass of sweater:

Mass of solution - Mass of NaCl

100 - 3.50 = 96.5 g

96.5 g in Kg :

96.5 / 1000 => 0.0965 Kg

Therefore ,calculate molality by using the following formula:

molality = number of moles of solute / mass of solution

molality = 0.059 / 0.0965

molality = 0.61 m

Hope That helps!

7 0

2 years ago

Element X has an electron configuration of 2-8-3. This element will combine with the phosphate ion to form a compound with the f

Alinara [238K]

X element can give 3 electrons, and ions X³⁺ can be formed.
Phosphate ion - (PO4)³⁻,
So compound will have formula X³⁺(PO4)³⁻,
XPO4

5 0

2 years ago

Read 2 more answers