Answer:
5a. 4w+24≤100
5b. Dimensions=31ft x 19 ft
Area = 589ft²
Step-by-step explanation:
l=w+12
p=2l+2w
p=2(w+12)+2w
p=2w+24+2w
p=4w+24
The farmer has 100ft of fencing, so maximum that the perimeter (p) can be is 100, meaning (4w+24) has to be less than or equal to 100:
4w+24≤100
For the largest possible perimeter, all 100 of fencing will be used, so allow 100 to be equal to 4w+24)
100=4w+24
4w=76
w=19ft
l=w+12
l=19+12
l=31ft
The dimensions are 31ft x 19ft.
Area=lw
=31*19
=589ft²
To do these problems, plug in a couple of values into the equations, and see the general shape of the graph. To ensure you were right, check them on an online graphing calculator. I highly recommend Desmos Graphing Calculator. Cheers!
Answer:
A
Step-by-step explanation:
to find (g ○ f)(3) , evaluate f(3) and substitute the value obtained into g(x)
f(3) = | 3 + 2 | = 5 , then
g(5) = - 5² = - 25
Answer: $270
Step-by-step explanation:
1. calculate how much he's getting paid per hour
- 360 / 12 = $30
2. calculate how much he's getting paid for 9 hours
- 30 * 9 = $270
Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.
Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.
<u>Average Rate of Change</u>
<em><u>Bird A</u></em>:
For the interval [0,18]:
x₁ = 0 f(0) = 8.3
x₂ = 18 f(18) = 9.1
Average =
Average =
Average = 0.045
<em><u>Bird B</u></em>: y = 3.6(1.06)x
For the interval [0,18]:
x₁ = 0 y = 3.6(1.06)0 = 0
x₂ = 18 y = 3.6(1.06)18 = 68.7
Average =
Average =
Average = 3.816
The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.