In the diagram, figure I is a square, and figures II and III are equilateral triangles. What is the value of x?
2 answers:
You might be interested in
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = = 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Answer:
x = -5
Step-by-step explanation:
We don't know what equation solver you're supposed to use. Here are the results from one available on the web.
