The products that would be formed if chlorine gas was bubbled <span>through a solution of sodium bromide would be sodium chloride and bromine gas. The reaction would be written as:
2NaBr + Cl2 = 2NaCl + Br2</span>
At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.
<h3>What is Avogadro's law?</h3>
Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."
It is expressed as;
V₁/n₁ = V₂/n₂
Given the data in the question;
- Initial amount of gas n₁ = 2moles
- Initial volume v₁ = 13.9L
- Final amount of gas n₁ = 3moles
V₁/n₁ = V₂/n₂
V₁n₂ = V₂n₁
V₂ = V₁n₂ / n₁
V₂ = (13.9L × 3moles) / 2moles
V₂ = 41.7molL / 2mol
V₂ = 20.85L
Therefore, at constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.
Learn more about Avogadro's law here: brainly.com/question/15613065
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In recent years, researchers have tried to capture the electrical current that bacteria generate through their own metabolism. So far, however, the transfer of the current from the bacteria to a receiving electrode has not been efficient at all.
Most definitely! Consider bacteria in a petri dish. Organisms need nutrition to survive, and when overcrowding is an issue (which by definition means that there is an insufficient amount of space/resources for the current population), organisms cannot survive and reproduce.
Answer:
11.58 g
Explanation:
First we convert the given masses of both reactants into moles, using their respective molar masses:
- 6.89 g CaO ÷ 56 g/mol = 0.123 mol CaO
- 13.79 g H₂O ÷ 18 g/mol = 0.766 mol H₂O
As<em> 1 H₂O mol reacts completely with 1 CaO mol,</em> and there are more H₂O moles than CaO moles, water is the non limiting reactant.
We calculate the mass of the reacting moles of water (the same number of CaO moles, 0.123):
- 0.123 mol H₂O * 18 g/mol = 2.21 g
Finally we <u>calculate how many grams of water remained after the reaction</u>:
- 13.79 g - 2.21 g = 11.58 g
