<em>Answer: h = 120 ft; w = 80 ft </em>
<em></em>
<em>A = 9600 ft^2</em>
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<em>Step-by-step explanation: Let h and w be the dimensions of the playground. The area is given by:</em>
<em></em>
<em>A = h*w (eq1)</em>
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<em>The total amount of fence used is:</em>
<em></em>
<em>L = 2*h + 2*w + w (eq2) (an extra distance w beacuse of the division)</em>
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<em>Solving for w:</em>
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<em>w = L - 2/3*h = 480 - 2/3*h (eq3) Replacing this into the area eq:</em>
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<em></em>
<em></em>
<em>We derive this and equal zero to find its maximum:</em>
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<em> Solving for h:</em>
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<em>h = 120 ft. Replacing this into eq3:</em>
<em></em>
<em>w = 80ft</em>
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<em>Therefore the maximum area is:</em>
<em></em>
<em>A = 9600 ft^2</em>
<em />
Answer:
4600
Step-by-step explanation:
We can write a proportion to find the total amount who attend university using the information given. A proportion is two equivalent ratios set equal to each other. Since 70% live on campus, then 30% live off campus and we are told that number is 1,380.
We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.
30y=100(1380)
30y=138000
y=4600.
There are 4600 students who attend the university.
AB = 2.894 inches
hope this helps
Answer:
4<C
<10
Step-by-step explanation:
Theorem: Given a triangle with sides A, B and C the sum of the lengths of any two sides of a triangle must be greater than the third side:
1. A+B>C
2. B
+C
>A
3. A+C>B
Thus given two sides of A=3 and B=7 C can be:
7
−3<C
<
7+3
C range
4<C
<10
320/240 = 1.33
1.33 = 133% (move the decimal point over two places to the right)
133% is your answer
hope this helps
