Answer:
This motion is known as Brownian motion.
Explanation:
This motion is known as Brownian motion.
Answer: 5.79 s
Explanation:
Vs=0 m/s starting speed(from rest)
Vf=325 km/h= 325*1000/3600= 90.28 m/s
a=15.6m/s²
Using equation for acceleration we can find out time :
a=(Vf-Vs)/t
t=(Vf-Vs)/a
t=(90.28 m/s-0m/s)/15.6 m/s²
t=5.79 s
Answer:
This situation is possible.
Explanation:
It is said in the problem that one morning two trains are speeding up from opposite directions onto the bridge. It may seem from this statement that the trains are arriving at the same time. But this should be a wrong assumption.
Because it is only said in the problem that the trains are passing the bridge on same morning. No explicit timing is given.
So it may so happen that both the trains pass the narrow bridge on the same morning but at two difeerent times, making no collision with each other.
Answer:
its 0 m/s^2 on khan
Explanation:
usually how i think of it if its below 15 N then its 0