The dimensions of the rectangular pen should be 15 by 20 feet and the maximum area is 1200 square feet.
Let the area be y .
Area = (base) × (height)
Base = 2x
Height = h
Let the area of the rectangular pens be y .
∴ y = 2xh
Perimeter of all the fencing = 4x+3h
∴ 4x+3h = 120
now we solve for h
3h = 120-4x
h = 40 - 4/3 x
Now we will substitute this value in the above first equation:
y = 2xh
or, y = 2x (40 - 4/3 x)
or, y = 80x - 8/3 x²
Now for the maximum area we have to find the first order differentiation of y
now,
dy /dx = 80 - 16/3 x
At dy/dx = 0 we get the value of x for which y is maximum.
80 - 16/3 x = 0
or, - 16/3 x = -80
or, x = 15 feet
Hence height = 40 - 4/3 x = 40 - 20 = 20feet
Maximum area = 2xh = 2×15×40 = 1200 square feet
The dimensions of the rectangular pen should be 15 by 20 feet and the maximum area is 1200 square feet.
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Answer:
The answer is D. Surface Tension. :) I am forsure this is correct but please let me know. If I am correct please rate me 5 and thank me and mark me brainlest :)
Step-by-step explanation:
The 2nd choice down in correct.
Answer:
Part A: C. 4 to 1
Part B: 2
Step-by-step explanation:
<h3>Part A: </h3>
What is the ratio of the number of students receiving a C and the number of students receiving an A?
<u>As per table given:</u>
- 12 students received a C and 3 students received a A
The ratio C/A is:
The correct answer choice is:
<h3>Part B: </h3>
Complete the statement:
For every student receiving a D, ______ students received a B.
<u>As per table given:</u>
- 4 students received a D and 8 students received a B
<u>The ratio D/B is:</u>
<u>The statement is:</u>
- For every student receiving a D, 2 students received a B.
The area under the graph of the continuous uniform distribution is 1.
a. The probability that the value will be between 5 and 7 is the area between 5 and 7.
b. The probability that the value will be between 2 and 3 is the are between 2 and 3.
c. The mean is given by:
d. The variance is given by:
The standard deviation is: