Answer: time t = 10s
Explanation:
Given;
Diameter = 8.0cm = 0.08m
Radius r = diameter/2 = 0.08/2 = 0.04m
Cord length d = 6.0m
Angular acceleration = 3.0rads/s2
Time = t
Converting the angular acceleration to linear acceleration
a = a* × r = 3.0 × 0.04 = 0.12m/s
d = vt + 1/2 (a × t^2)
Initial velocity v = 0, vt = 0 therefore;
d = 1/2 ( a × t^2)
t = √(2d/a)
t = √ [(2× 6)/0.12]
t = 10s
Answer:
3.33m
Explanation:
Given parameters:
Force applied =500N
Elastic constant = 150N/m
Unknown:
Amount of stretch or extension = ?
Solution:
To solve this problem use the expression below:
F = k e
F is the force applied
k is the elastic constant
e is the extension
So;
500 = 150 x e
e = = 3.33m
Answer:
0.82 m
Explanation:
The ball is in free fall - uniform accelerated motion with constant acceleration downward, (acceleration of gravity). So we can use the following suvat equation to solve the problem:
where
v is the final velocity
u = 4 m/s is the initial velocity
a is the acceleration
s is the displacement
At the maximum displacement, v = 0 (the velocity becomes zero). Substituting and solving for s, we find:
Answer:
The electric field always decreases.
Explanation:
The electric field due to a point charge is given by :
Where
k = electric constant
q = charge
r = distance from the charge
It is clear from the above equation that as the distance from the charge particle increases the electric field decreases. As you move away from a positive charge distribution, the electric field always decreases. Hence, the correct option is (c) "Always decreases".