Answer:
The given functions are
The sine function has a standard period of 
by definition. However, this might change if we use a factor as coefficient of the x-varible, but in this case we don't have that.
Therefore, the period of both trigonometric functions is .
Now, the images of each function is the y-variable set values that defines each function.
So, the function has an image defined by the set ![[-3,5]](https://tex.z-dn.net/?f=%5B-3%2C5%5D)
. It's impotant to notice that the range of a standard function is [-1,1], however, in this case, the function was shifted 1 unit up and it was streched by a factor of 4, that's why the standard image changes to .
About the second function , the image set is ![[-2,2]](https://tex.z-dn.net/?f=%5B-2%2C2%5D)
, because the function was streched by a factor of 2.
Additionally, the image attached shows the graph of the given functions.
11+13= 24
13-11= 2
The numbers are 13 and 11.
I hope this helps!
~kaikers
Answer:
40%
Step-by-step explanation:
Answer:
f[g(x)]= 7x + 27
Step-by-step explanation:
g(x) = x + 2,
f(x) = 7x + 13,
f[g(x)] means you substitute the value of g(x) into the variable of f(x);
Which is 7( x+2) + 13 = 7x +14 +13
= 7x + 27
Since each table had 7 women and 3 men at each table, that would mean each table has 10 people. Since there are 9 tables he was waiting on, and 10 people at each table, multiply 9 x 10, and you will find that he served 90 people in total.
