All vascular plants have parenchyma, collenchym<span>Vascular tissue transports food, water, hormones and minerals within the plant. Vascular tissue includes </span>xylem<span>, </span>phloem<span>, parenchyma, and cambium cells.</span>a, and sclerenchyma cells. Hoped it help!
Answer:
v = 88.89 [m/s]
Explanation:
To solve this problem we must use the principle of conservation of momentum which tells us that the initial momentum of a body plus the momentum added to that body will be equal to the final momentum of the body.
We must make up the following equation:
where:
F = force applied = 4000 [N]
t = time = 0.001 [s]
m = mass = 0.045 [kg]
v = velocity [m/s]
Answer:
Major, weight-bearing structures are the bones of the body that are strong and dense to be able to bear the weight of the body. The major, weight-bearing structures of cat and human skeletons are :
Human skeleton: The body weight of an individual is on his pelvic girdles that are attached to the bones of lower limbs. Thigh bones, leg bones, and bones of feet comprise lower limbs The lower limbs consist of the thigh, the leg, and the foot.
Cat skeleton: cats are quadrupedal so it bears all the body weight on shoulders and legs that includes the Scapula and pelvis.
Answer:
1.34 × 10⁻⁵
Explanation:
Let's consider the acid dissociation of propanoic acid.
CH₃CH₂COOH(aq) + H₂O(l) ⇄ CH₃CH₂COO⁻(aq) + H₃O⁺(aq)
We can find the acid dissociation constant (Ka) using an ICE chart.
CH₃CH₂COOH(aq) + H₂O(l) ⇄ CH₃CH₂COO⁻(aq) + H₃O⁺(aq)
I 0.65 0 0
C -x +x +x
E 0.65 - x x x
We know that [CH₃CH₂COO⁻] = [H₃O⁺] = x = 2.95 × 10⁻³ M
[CH₃CH₂COOH] = 0.65 - 2.95 × 10⁻³ = 0.64705 M
Ka = [CH₃CH₂COO⁻].[H₃O⁺]/[CH₃CH₂COOH]
Ka = (2.95 × 10⁻³)²/0.64705
Ka = 1.34 × 10⁻⁵