Answer:
$1,061
Step-by-step explanation:
Simply find out 2% of the value before, then do that two times more.
Answer:
243 in²
Step-by-step explanation:
Step 1. Calculate the<em> base and height </em>of the rectangle
We have two conditions:
(1) 2b+ 2h = 72 in
(2) b = 3h Substitute in (1)
2(3h) + 2h = 72 Remove parentheses
6h + 2h = 72 Combine like terms
8h = 72 Divide by 6
h = 9 in Substitute in(2)
b = 3 × 9
b = 27 in
Step 2. Calculate the area of the rectangle
A = bh
A = 27 × 9
A = 243 in²
The area of the rectangle is 243 in².
I think it’s QT EJ and HA
Hello,
f(x)=2x^2-3x+4
f(3a)=2(3a)^2-3*(3a)+4=2*9a²-9a+4=18a²-9a+4
Complete Question
Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The parts of this exercise outline a strong induction proof that P (n) is true for n ≥ 18.
Show statements P (18), P (19), P (20), and P (21) are true, completing the basis step of the proof.
Answer:
P(18) is true
P(19) is true
P(20) is true
P(21) is true
Step-by-step explanation:
a. When n = 18
18 cents can be formed using two 7cents and one 4cents
i.e. 2 * 7 + 4 = 18
So, P(18) is true
b. When n = 19
19 cents can be formed using one 7cents and three 4cents
i.e. 1 * 7 + 3 * 4 = 19
So, P(19) is true
c. When n = 20
18 cents can be formed using five 4cents
i.e. 5 * 4 = 20
So, P(20) is true
d. When n = 21
18 cents can be formed using three 7cents
i.e. 3 * 7 = 21
So, P(21) is true