For 1 - 12y < 3y+1; y > 15
For 2 - 6y > 4 + 4y; y < -0.2
The given inequalities are:
1 - 12y < 3y + 1
2 - 6y > 4 + 4y
For 1 - 12y < 3y + 1:
1 - 12y < 3y + 1
Collect like terms
-12y - 3y < 1 - 1
-15y < 0
Multiply both sides by -1
-1(-15y) > 0(-y)
15y > 0
Divide both sides by 15
y > 0/15
y > 15
For 2 - 6y > 4 + 4y
Collect like terms
-6y - 4y > 4 - 2
-10y > 2
Multiply both sides by -1
-1(-10y) < 2(-1)
10y < -2
y < -2/10
y < -0.2
Learn more here: brainly.com/question/11316045
Answer:
8z+15
Step-by-step explanation:
Answer:
When you have large numbers to divide,
draw a tableau for long division on the side.
Write the steps that will be your guide,
D, M, S, B and R – Abide by to long divide!
Step-by-step explanation:
Step-by-step explanation:
10.35 according to chemistry . product
Answer:
Here we can use the relationship:
Distance = time*speed.
When Jose walks, his speed is 4 mph.
Then if he walks for X hours, the distance that he will travel is:
D = 4mph*X
When Jose runs, his speed is 8mph.
Then if he runs for T hours, the distance that he will travel is:
D´ = 8mph*Y
And we know that he travels in total 20 miles, then we must have that:
D + D´= 20mi
This leads to:
4mph*X + 8mph*Y = 20mi
Where X is the time that he walked, and Y is the time that he runed.
Then the equation that represents the different amounts of times that Jose runs and walks is:
4mph*X + 8mph*Y = 20mi
Where we can not really find the solutions for Y and X, because there is only one equation and two variables.