0 or 1 or more than one for zero functions
7cos(x) + 1 = 6sec(x)
7cos(x) + 1 = 6/cos(x)
7cos^(x) + cos(x) = 6
7cos^(x) + cos(x) - 6 = 0
[7cos(x) - 6][cos(x) + 1] = 0
cos(x) = 6/7 , x = arccos(6/7) and
cos(x) = -1, x = 180
Answer:
24 and 9
Step-by-step explanation:
Hi there!
Let x be equal to the larger integer.
Let y be equal to the smaller integer.
<u>1) Construct equations</u>
- (The sum of two integers is 33)
- (The larger is 6 more than twice the smaller)
<u>2) Solve for one of the integer</u>
Isolate x in the first equation
Plug the first equation into the second
Combine like terms
Therefore, the smaller integer is 9.
<u />
<u>3) Solve for the other integer</u>
Plug in y (9)
Therefore, the larger integer is 24.
I hope this helps!
Answer:
The 4th one is the least so you would put that as the first one, then the 2nd one, then the 1st one, then the 3rd one.
Step-by-step explanation:
The fourth one is first because 10 to the power of 0 is 0 times 10 to the power of 1 is still 0 minus 1 to the power of 10 is 1 so 0 minus 1 is -1. The second one is second because 10 to the power of 0 times 10 to the power of 1 is 0, times 1 to the power of 10 is still 0. The first one is third in line because 10 to the power of 0 plus 10 to the power of 1 is 10 times 1 to the power of 10 is 10. The third one is last because its the greatist, 10 to the power of 0 plus 10 to the power of 1 is 10 plus 1 to the power of 10 is 11.
Answer:
(a). 15
(b). 78
Step-by-step explanation:
Growth of the population of a fruit fly is modeled by
N(t) =
where t = number of days from the beginning of the experiment.
(a). For t = 0 [Initial population]
N(0) =
=
=
= 15
Initial population of the fruit flies were 15.
(b).Population of the fruit fly colony on 11th day.
N(11) =
=
=
=
=
= 77.82
≈ 78
On 11th day number of fruit flies colony were 78.