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2 years ago

Evaluate x (5-y) ; use x=6,and y=1

Mathematics

1 answer:

Zolol [24]2 years ago

6 0

Answer:

Step-by-step explanation:

x (5-y)

Let x=6,and y=1

6(5-1)

PEMDAS says parentheses first

6(4)

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What is the common difference or common ratio of the sequence 2,5,8,11...? A. 1 B. 3 C. 5 D. 7

RUDIKE [14]

Answer:

B. 3

Step-by-step explanation:

A common difference in an arithmetic sequence is the value the terms in the sequence vary from one to another.You can find one term to another by adding or subtracting the common difference.

In this case, the terms are 2,5,8,11,.....

From the first term to the second term, the difference is, 5-2=3

From the second term to the third term, the difference is, 8-5=3

From the third term to the fourth term the difference is=11-8=3

Hence the common difference in this arithmetic sequence is 3

5 0

2 years ago

Read 2 more answers

1/4 :10=x:4 find x I need the answer now

Naily [24]

Answer:

x=1.6

Step-by-step explanation:

Multiply each number by 4 to make wholes and than just cross multiply.

3 0

2 years ago

What is the value of x? 12 units 15 units 20 units 25 units

Firlakuza [10]

Answer:

The answer is 12 units.

Step-by-step explanation:

Looking at the figure we see that

$(1).9^2+x^2=SR^2$

$(2).16^2+x^2=RQ^2$ and

$(3).SR^2+RQ^2=(9+16)^2$

Now from equations (1) and (2) we have values for $SR^2$ and $RQ^2,$ so we put those into the equation (3) and get:

$9^2+x^2+16^2+x^2=(9+16)^2$

$\rightarrow 337+2x^2=625$

$\boxed{\therefore x= 12.}$

Therefore the answer is 12 units.

6 0

2 years ago

Read 2 more answers

Find the coordinates of the circumcenter of △PQR with vertices P(−2,5), Q(4,1), and R(−2,−3).

mel-nik [20]

Answer: (1/3,2)

Step-by-step explanation:

Let O(x,y) be the circumference of the triangle PQR,

Thus, by the property of circumcenter all the vertices of the triangle are at same distance from this circumcenter.

Thus, PO = QO

By the distance formula,

$(x+2)^2+(y-5)^2 = (x-4)^2+(y-1)^2$

$\impliesx^2+ 4x + 4 + y^2+ 25 - 10 y = x^2+16 - 8 x + y^2+1 - 2y$

$\implies 4x + 4 + 25 - 10 y = 16 - 8 x + 1 - 2y$

$\implies 4x +8x-10y+2y = 16 + 1 -25-4$

$\implies 12x - 8y = 17 - 29$

$\implies 12 x - 8 y = - 12$ ---------(1)

Similarly, QO = RO

$\implies (x-4)^2 + (y-1)^2 = (x+2)^2+(y+3)^2$

$\implies x^2 + 16 - 8x + y^2+ 1 - 2y = x^2+ 4 + 4 x +y^2+ 9 + 6 y$

$\implies 16 - 8x + 1 - 2y = 4 + 4 x + 9 + 6 y$

$\implies - 8x -4x-2y-6y=4+9-16-1$

$\implies -12 x - 8 y = 13 - 17$

$\implies 12 x + 8 y = 4$ ------------(2)

By adding equation (1) and (2),

24 x = - 8

x = 1/3

By putting this value in equation (1),

We get,

Thus, 4 - 8 y = -12

8 y = 16

y = 2

7 0

2 years ago

Explain please thanks :)

dem82 [27]

Answer:

Step-by-step explanation:

The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.

Okay, on to the problem:

We can do one digit at a time.

First digit:

There are 4 digits that we can choose from. (3, 4, 6, and 7)

Second digit:

No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.

Third digit:

Using the same logic, there are only 2 options left.

We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.

Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.

8 0

1 year ago

Evaluate x (5-y) ; use x=6,and y=1​

Evaluate x (5-y) ; use x=6,and y=1