Answer:
∠ WZX = 50°
XW is not an altitude.
Step-by-step explanation:
16. See the attached figure.
XW is the angle bisector of ∠ YXZ, hence, ∠ WXY = ∠ WXZ
Now, given that ∠ YXZ = 8x + 34 and ∠ WXY = 10x - 13
Hence, ∠ YXZ = 2 ∠ WXY
⇒ 8x + 34 = 2(10x - 13)
⇒ 8x + 34 = 20x - 26
⇒ 12x = 60
⇒ x = 5.
Hence, ∠ XZY = ∠ WZX = 10x = 50° (Answer)
Now, ∠ WXZ = ∠ WXY = 10x - 13 = 37°
Hence, from Δ WXZ,
∠ WZX + ∠ WXZ + ∠ XWZ = 180°
⇒ 50° + 37° + ∠ XWZ = 180°
⇒ ∠ XWZ = 93° ≠ 90°
Hence, XW is not an altitude. (Answer)
3√10^4x is equivalent to -√10 3/4^x and -4√10^3x they are all equivalent
D) Line JK
<----->
JK
<em>H</em><em>o</em><em>pe </em><em>it </em><em>helps </em><em>:</em><em>)</em>
Answer: x=80°
Explanation:
To find the exterior angle x we first need to find the last corner angle (a) of the triangle. The angles of triangles add up to 180° so we can use the formula: 25+55+a=180
Solving formula:
25+55+a=180
80+a=180
(Subtract 80 from both sides)
a=100°
Now that we know a=100 we can find the exterior angle. a+x=180 because the angles are on a straight line which equals 180°
a+x=180
100+x=180
(Subtract 100 from both sides)
x=80°
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Answer:
the first step is correct
Step-by-step explanation:
the first step is correct
then draw 2 circles with the same radius with centre D and E ( the point BC intersect the first circle )
Where the 2 circles are intersecting is the point F
Then BF is the bisector