Answer:
x= -2 and y= 8
Step-by-step explanation:
8x+5y=24-------A
y=-4x---------B
Putting the value of y from B in A
8x+5(-4x)=24
8x +(-20x)= 24
8x-20x=24
-12x=24
x= -24/12
x=-2--------C y =-4(-2)=8
Answer:
ans: ln (5/8) , ln5 - ln8
Step-by-step explanation:
8e^x -5 = 0
e^x = 5/8
x = ln (5/8)
x = ln5 - ln8
The answer to number 5 is 1/4 of a foot. there are 12 inches in a foot. 12 divided by 4 is 3. So 12 inches divided by 4 sections is 3 inches in each section.
10^3 CDs with CD = $12 then total CDs earnings is (10^3)(12) = $12,000
10^2 CD players with CD plater = $35 then total CD player earnings is (10^2)(12) = $1,200
Total store earnings = ($12,000 + $1,200) = $13,200
Supposing a normal distribution, we find that:
The diameter of the smallest tree that is an outlier is of 16.36 inches.
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We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>
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In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:
- The Z-score measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u>
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In this problem:
- Mean of 8.8 inches, thus .
- Standard deviation of 2.8 inches, thus .
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The interquartile range(IQR) is the difference between the 75th and the 25th percentile.
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25th percentile:
- X when Z has a p-value of 0.25, so X when Z = -0.675.
75th percentile:
- X when Z has a p-value of 0.75, so X when Z = 0.675.
The IQR is:
What is the diameter, in inches, of the smallest tree that is an outlier?
- The diameter is <u>1.5IQR above the 75th percentile</u>, thus:
The diameter of the smallest tree that is an outlier is of 16.36 inches.
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A similar problem is given at brainly.com/question/15683591