Answer:
A reasonable way to use them is to code the five most-common strings in the ... bytes, compared to a bitmap size of only 6 × 8 bits = 6 bytes. ... Columns 2, 4, 5, and 7 yield the six runs 0,5,1,1,1,eol each. ... 2.3: Replacing 10 by 3 we get x = k log2 3 ≈ 1.58k. ... Table Ans.3: Probabilities and Entropies of Two Symbols.
Step-by-step explanation:
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Answer:
volume = 13500
Step-by-step explanation:
For a given pyramid, its volume can be determined by:
volume of pyramid =
Where: l is the base length, w is the base width and h id the height of the pyramid.
For the given question, l 30 cm, w = 30 cm and h = 45 cm.
So that,
volume =
=
= 13500
volume = 13500
The volume of the pyramid is 13500 .
X = 29 and y = 101.
To find this, you need to set up an equation.
6x - 95 = 79. Once you solve this, x would equal 29.
Since 6x - 95 and y are on a straight line, they would have to equal 180. So you make another equation except you plug in 29 for x this time.
6(29) - 95 + y = 180. Once you solve this, y would equal 101.
Distance between points (3, -16) and (-10, -12) is 13.6015
It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>
</span><span>In notation we write respectively
</span>
Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence
Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²
That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers