Answer:
2. 5 miles
Step-by-step explanation:
Given that:
Rental cost = $30
Cost per mile driven = 18 cent
Daily budget = $75
Greatest distance you can drive each day while staying within budget :
Rental cost + (cost per mile driven * distance) ≤ daily budget
$30 + 18d ≤ $75
18d ≤ 75 - 30
18d ≤ 45
d ≤ 45 / 18
d ≤ 2.5
Greatest distance you can drive each day while staying within budget is 2.5 miles.
Answer:
3x + 1y = $163
2x + 3y =$174
Step-by-step explanation:
Adult tickets to space amusement park cost x dollars children’s tickets cost y dollars.
Henson family bought 3 adults and 1 child's tickets for $163
x + y = 163
3x + 1y = 163
The Garcia family bought 2 adults and 3 child’s ticket for $174.
x + y = $174
2x + 3y = $174
Therefore the equations representing both families cost are
Henson family
3x + 1y = $163
Garcia family
2x + 3y = $174
Answer:
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2 is 42 but i’m not sure about one
The correct answer would be -3/8 or in decimal form -0.375 :)