30(-2/5)²(5/8) = 30*(4/25)*(5/8) = 30*4/(5*8) = 3
Given:
A regular polygon with three vertices and side 14 cm.
To find:
Area of the regular polygon.
Solution:
We know that, a regular polygon has equal sides and equal interior angles.
The given regular polygon has three equal sides, it means it is an equilateral triangle.
The area of an equilateral triangle is:
Where, a is the side length of the triangle.
Putting 
, we get
Therefore, the area of given regular polygon is 84.9 cm².
Answer:
(closed circle on 6)————>
<—————(open circle on -1)
Step-by-step explanation:
Im a keep editing since this is timed.
#1 x-8a/6=3a-2x
Multiply each term by 6 to remove fraction .
6(x-8a/6)= 3a(6)-2x(6)
X-8a=18a-12x
Add 12x both sides
X+12x-8a=18a-12x+12x
13x-8a= 18a
Add8a both sides
13x-8a+8a=18a+8a
13x=26a
Divide each side by 13
13x/13=26a/13
X= 26a/13
Reduce and cancel common factor .
X= 13(2a)/13(1)
X=2a/1
X=2a
Problem #2
3x-2a=7a find a
Subtract 3x both sides
3x-3x-2a=7a-3x
-2a=7a-3x
Subtract 7a both sides
-2a-7a=7a-7a-3x
5a=-3x
Divide both sides by 5
5a/5=-3x/5
A= -0.6 or -3/5
Problem#3
3(bx-2ab)=b(x-7a)+3ab
Distributed property
3(bx)+3(-2ab)=b(x)+b(-7a)+3ab
Simplify
3bx-6ab=bx-7ab+3ab
Add -7a plus 3ab on right side
3bx-6ab= bx-4ab
Subtract bx both sides
3bx-bx-6ab= bx -bx -4ab
Simplify
2bx-6ab= -4ab
Add 6ab both sides
2bx-6ab+6ab=6ab-4ab
2bx=2ab
Divide 2b both sides
X= 2ab/2b
Cancel 2 common
X= ab/b
X=a
Answer = 1/2
- I’m pretty sure that is it... hope this works for ya!!
