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2 years ago

Give the systematic name for the following compound

Chemistry

1 answer:

Zielflug [23.3K]2 years ago

8 0

Answer:

2,4–dimethylhexane.

Explanation:

To name the above compound, we must do the following:

1. Locate the longest continuous carbon chain. This gives the parent name. In this case, the longest chain is carbon 6 i.e Hexane.

2. Identify and Locate the position of the substituent group attached. In this case, the substituent group attached is methyl i.e CH3 and it is at carbon 2 and 4.

3. Combine the above to get the name.

Therefore, the name of the compound is:

2,4–dimethylhexane.

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The equilibrium 2NO(g)+Cl2(g)⇌2NOCl(g) is established at 500 K. An equilibrium mixture of the three gases has partial pressures

QveST [7]

Answer:

For A: The $K_p$ for the given reaction is $4.0\times 10^1$

For B: The $K_c$ for the given reaction is 1642.

Explanation:

The given chemical reaction follows:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

For A:

The expression of $K_p$ for the above reaction follows:

$K_p=\frac{(p_{NOCl})^2}{(p_{NO})^2\times p_{Cl_2}}$

We are given:

$p_{NOCl}=0.24 atm\\p_{NO}=9.10\times 10^{-2}atm=0.0910atm\\p_{Cl_2}=0.174atm$

Putting values in above equation, we get:

$K_p=\frac{(0.24)^2}{(0.0910)^2\times 0.174}\\\\K_p=4.0\times 10^1$

Hence, the $K_p$ for the given reaction is $4.0\times 10^1$

For B:

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = $4.0\times 10^1$

$K_c$ = equilibrium constant in terms of concentration = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = 500 K

$\Delta ng$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-3=-1$

Putting values in above equation, we get:

$4.0\times 10^1=K_c\times (0.0821\times 500)^{-1}\\\\K_c=\frac{4.0\times 10^1}{(0.0821\times 500)^{-1})}=1642$

Hence, the $K_c$ for the given reaction is 1642.

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2 years ago

Which of the following results in a chemical change in matter?

kodGreya [7K]

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2 years ago

What is the minimum cation-to-anion radius ratio (rC/rA) for an octahedral interstitial lattice site?

mash [69]

Answer:

0. 414

Explanation:

Octahedral interstitial lattice sites.

Octahedral interstitial lattice sites are in a plane parallel to the base plane between two compact planes and project to the center of an elementary triangle of the base plane.

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2 years ago

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Neporo4naja [7]

Answer:

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2 years ago

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Dmitriy789 [7]

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2 years ago